Grade 11Mechanics

Two balls of equal masses are thrown upward, along the same vertical line at an interval of 2 seconds, with the same initial velocity of 14m/s. Then this collide at a height of (Take g = 10m/s² )

Ayush kumar

8 Years agoGrade 11

1 Answer

Aryan Khera

7 Years ago

Let the displacement by ball 1 be s₁and displacemnt by ball 2 be s₂

Then,

S₁₌14*t -1/2*10*t²

=14t - 5t²

Similarly,

S₂=14(t-2) -1/2*10*(t-2)²

As the collide,

S₁=S₂

14t -5t²⁼14(t-2) - 5(t-2)²

on solving we get

t=4.8 sec

At t=4.8 sec,

S₁₌14*4.8 -5(4.8)²

S₁=48 cm as height can never be negative.

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Two balls of equal masses are thrown upward, along the same vertical line at an interval of 2 seconds, with the same initial velocity of 14m/s. Then this collide at a height of (Take g = 10m/s2 )

Ayush kumar

1 Answer

Aryan Khera

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Two balls of equal masses are thrown upward, along the same vertical line at an interval of 2 seconds, with the same initial velocity of 14m/s. Then this collide at a height of (Take g = 10m/s² )

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