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Two balls are projected at different angles from the same place and with the same initial speed of 50 m/s. Both balls have the same range of 216 m. The difference in their times of flight is close to

    Aditi , 7 Years ago
    Grade 12th pass
    anser 1 Answers
    Arun
    Dear Aditi
     
    R1 = R2 = 50² sin (2theta)1 /g = 50² sin (2 theta)2/g
    2160/2500 = sin(2theta)1
    Sin(2 theta)1 \approx sqrt(3) /2
    Hence 
    (2 theta)1 = 60°
    tehta)1 = 30° 
    Now as sin (2 theta)1 = sin (2 theta)2
    Hence 
    2 theta2 = 120°
    Theta)2 = 60°
    Hence
    T1 = 2 *50 sin 30/10 = 5 sec
    T2 = 2 *50 * sin60 /10 = 5 * sqrt(3) sec
    Hence
    T2 - T1 = 5 ( sqrt(3) -1) sec
    Last Activity: 7 Years ago
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