×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
To cross the river in the shortestdistance,aswimmer shoule swim making angle ‘x’ with the upstream.what is ratio of time taken to swim across in the shortest time to that in swimming across over shortest distance.(assume speed of the swimmer in the still water is greater than the speed of river flow.
To cross the river in the shortestdistance,aswimmer shoule swim making angle ‘x’ with the upstream.what is ratio of time taken to swim across in the shortest time to that in swimming across over shortest distance.(assume speed of the swimmer in the still water is greater than the speed of river flow.

```
4 years ago

Vikas TU
14149 Points
```							Crossing the rivver in shortest time = >t = l/Vcosthetha where thetha is the angle he make with the vertical.And for shortest path he has to travel perpendicularly with t = l/root(V^2 – Vr^2)
```
4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions