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Grade 12Mechanics

three particles, located initailly on the vertices of an equilateral triangle of side 9cm, start moving with a constant speed towards each other in a cyclic manner, forming spiral loci that converge at the centroid of the triangle. Find the length of one such spiral locus in cm.

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8 Years agoGrade 12
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1 Answer

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ApprovedApproved Tutor Answer11 Months ago

To find the length of one spiral locus formed by the three particles moving towards each other, we need to understand the nature of their motion and the geometry involved. The particles start at the vertices of an equilateral triangle and move towards each other, creating a spiral path that ultimately converges at the centroid of the triangle.

Understanding the Motion

Each particle moves directly towards the other two particles. As they do this, they not only move closer to the centroid but also change their direction continuously, resulting in a spiral path. The key to solving this problem lies in recognizing that the particles maintain a constant speed and the symmetry of their motion.

Key Parameters

  • Initial Side Length: 9 cm
  • Initial Configuration: Equilateral triangle
  • Centroid: The point where all three medians intersect, located at a distance of 3 cm from each vertex.

Calculating the Length of the Spiral Locus

The length of the spiral path can be derived from the properties of logarithmic spirals. In this case, the particles will trace out a path that can be approximated by a logarithmic spiral as they converge towards the centroid.

Using the Spiral Length Formula

The length \( L \) of a logarithmic spiral can be expressed in terms of the initial distance \( r_0 \) (the initial side length of the triangle) and the angle \( \theta \) through which the particles rotate. The formula for the length of one complete spiral can be given as:

\[ L = \frac{r_0}{\sin(\theta)} \]

In our case, the angle \( \theta \) is \( 60^\circ \) (or \( \frac{\pi}{3} \) radians) since the particles are moving towards each other at the vertices of an equilateral triangle. Thus, we can substitute the values:

Substituting Values

Given that \( r_0 = 9 \) cm and \( \theta = 60^\circ \), we can calculate:

\[ L = \frac{9}{\sin(60^\circ)} \]

We know that \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \). Therefore, substituting this value gives us:

\[ L = \frac{9}{\frac{\sqrt{3}}{2}} = 9 \cdot \frac{2}{\sqrt{3}} = \frac{18}{\sqrt{3}} = 6\sqrt{3} \text{ cm} \]

Final Result

The length of one spiral locus traced by each particle as they converge at the centroid of the triangle is approximately:

Length of the spiral locus: 6√3 cm

This result illustrates not only the beauty of geometric motion but also the fascinating interplay between linear and angular dynamics in a system of particles. Each particle's path is a perfect example of how simple rules can lead to complex behaviors in physics and mathematics.