MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass 
        
Three particles each of mass m are situated at the vertices of an equilateral triangle of side a .Only mutual gravitational force act between them .It is desired that each particle is moving in a circle while maintaining mutuat separation a.Find initial velocity that should given to each particle and also time period of circular motin.
10 months ago

Answers : (1)

View Solution
Arun
22533 Points 
							
 
Dear Anshul
 
I am getting my answer as 
velocity = sqrt (Gm/a)
 
please let me know if thisbis correct then I will share my solution.
 
 
 
 
Regards
Arun (askIITians forum expert)
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Mechanics

A Utube contains oil carbon tetrachloride and water as shown in the figure the density of oil is 0.8... Answer & Earn Cool Goodies
A cylinder with angular velocity is dropped the number of roatation made by it before stops and the... Answer & Earn Cool Goodies
0.4i^+0.8j^+bk^ is unit vector. ,what is the value of b?
A swimmer crosses a river in shortest distance. If he tries to swim at 4 km/ hr maintaining 120 with...
a bolck lying ona inclined plane has a weight os 50N .It is just begins to slide down when the...
View all Questions »


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details