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`        Three identical rods each of mass 'm' and length 'l' form an equilateral triangle moment of inertia about one of the side is ?`
one year ago

## Answers : (4)

Arun
23479 Points
```							It is 2ml^2/3as about axis of rotation moment of inertia would be 0moment of inertia of rod about axis is ml^2/3therefore moment of inertia of triangle will be (about one of the side)ml^2/3+ml^2/3+0=2ml^2/3
```
one year ago
Ass satwik
12 Points
```							How ml^2/3?
```
one year ago
Ritika Chitlangia
15 Points
```							it is ml2/2
I = (ML2sin260*)/3 + (ML2sin260*)/3
I = ML2/2
```
one year ago
Abhinav Srivastava
13 Points
```							As one of the rod acts as axis so moment of inertia about other 2 rods have to be calculated,Two rods each of mass m could be substituted for one rod of mass 2m but of length √3l/2 and then moment of inertia can be calculated as for a uniform rod rotated from one end; 2m×(√3l/2)^2÷3 = ml^2/2
```
8 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions