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        Three identical particles each of mass m are placed at the corners of an equilateral triangle of side l. Also obtain the potential at centre of the triangle
2 years ago

Sidharth Shambu
24 Points
							Potential = -Gm/rDistance of particle from center of the triangle = L / $\sqrt$3so = 3*(-Gm/(L / $\sqrt$3 ))     =  – 3$\sqrt$3Gm/L

2 years ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions