Three blocks of masses m1=4kg m2=2kg m3=4kg are connected with ideal strings passing over a smooth massless pulley as shown in figure.The acceleration of blocks will be 2 m/s2 2) 4m/s2 3) 3m/s2 4) 5m/s2

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Saurav · Answer

the answer is A 2m/s 2 the question is preety simple just assume m 1 & m 2 as one block with mass 6Kg now total force causing accelaratio=(6-4) X g =2g aceleration =f/m =2g/(4+2+4) =2 m/s 2 please approve

Himanshi Birla · Answer

Consider m2 and m1 combined so the mass formed is 6 Kg Now using formula a=( m1 - m2 ) g m1 +m2 a= (6-4)10 6+4 a=2m/s2

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Three blocks of masses m1=4kg m2=2kg m3=4kg are connected with ideal strings passing over a smooth massless pulley as shown in figure.The acceleration of blocks will be 2 m/s2 2) 4m/s2 3) 3m/s2 4) 5m/s2

Three blocks of masses m1=4kg m2=2kg m3=4kg are connected with ideal strings passing over a smooth massless pulley as shown in figure.The acceleration of blocks will be

2 m/s2 2) 4m/s2 3) 3m/s2 4) 5m/s2

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Three blocks of masses m1=4kg m2=2kg m3=4kg are connected with ideal strings passing over a smooth massless pulley as shown in figure.The acceleration of blocks will be 2 m/s2 2) 4m/s2 3) 3m/s2 4) 5m/s2

Three blocks of masses m1=4kg m2=2kg m3=4kg are connected with ideal strings passing over a smooth massless pulley as shown in figure.The acceleration of blocks will be 2 m/s2 2) 4m/s2 3) 3m/s2 4) 5m/s2

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Three blocks of masses m1=4kg m2=2kg m3=4kg are connected with ideal strings passing over a smooth massless pulley as shown in figure.The acceleration of blocks will be

2 m/s2 2) 4m/s2 3) 3m/s2 4) 5m/s2