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Grade 11Mechanics

Three blocks of masses 6kg,4kg,2kg are pulled on a rough surface by applying a constant force 20N .The values of coefficient of friction bet blocks and surface are shown.(a)in the arrangement shown tension in the string connecting 4kg and 6kg masses is (b)friction force on 4kg block is (c)friction force on 6kg block is

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7 Years agoGrade 11
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To solve this problem, we need to analyze the forces acting on each block and how they interact with one another. We have three blocks with masses of 6 kg, 4 kg, and 2 kg, being pulled by a constant force of 20 N on a rough surface. The frictional forces will depend on the coefficient of friction between the blocks and the surface. Let's break this down step by step.

Understanding the Forces at Play

First, we need to identify the forces acting on each block. The applied force of 20 N is acting on the entire system, while frictional forces will oppose this motion. The tension in the string connecting the 4 kg and 6 kg blocks will also play a role in the dynamics of the system.

Calculating the Frictional Forces

Assuming we have the coefficients of friction (let's denote them as μ1 for the 6 kg block, μ2 for the 4 kg block, and μ3 for the 2 kg block), we can calculate the frictional forces using the formula:

  • Friction Force (F_f) = μ × Normal Force (N)

The normal force for each block is equal to its weight, which can be calculated as:

  • N = mass × g (where g = 9.81 m/s², the acceleration due to gravity)

Step-by-Step Calculations

Let's denote the blocks as follows:

  • Block A (6 kg)
  • Block B (4 kg)
  • Block C (2 kg)

1. **Calculate the Normal Forces:** - For Block A: N_A = 6 kg × 9.81 m/s² = 58.86 N - For Block B: N_B = 4 kg × 9.81 m/s² = 39.24 N - For Block C: N_C = 2 kg × 9.81 m/s² = 19.62 N

2. **Calculate the Friction Forces:** - Friction on Block A: F_fA = μ1 × N_A - Friction on Block B: F_fB = μ2 × N_B - Friction on Block C: F_fC = μ3 × N_C

3. **Determine the Total Friction Force:** - The total friction force opposing the applied force will be the sum of the friction forces on all blocks.

Finding Tension in the String

Next, we need to find the tension in the string connecting the 4 kg and 6 kg blocks. The net force acting on the 4 kg block can be expressed as:

  • Net Force (F_net) = Applied Force - Total Friction - Tension

Using Newton's second law (F = ma), we can express the acceleration of the system:

  • F_net = (Total Mass) × a

Where the total mass is the sum of all blocks (6 kg + 4 kg + 2 kg = 12 kg). We can rearrange this to find the acceleration and then use it to find the tension in the string.

Final Steps

1. **Calculate the acceleration (a):** - a = (Applied Force - Total Friction) / Total Mass

2. **Substitute the acceleration back into the equation for the 4 kg block to find the tension (T):** - T = F_net_B + F_fB

3. **Repeat the process for the 6 kg block to find its friction force.**

Summary of Results

After performing these calculations with the specific coefficients of friction, you will arrive at the values for:

  • The tension in the string connecting the 4 kg and 6 kg blocks
  • The friction force acting on the 4 kg block
  • The friction force acting on the 6 kg block

By following these steps and substituting the actual coefficients of friction, you can find the required values. If you have those coefficients, I can help you with the exact calculations!