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Three ants are sitting on the vertices of an equilateral triangle of side a. At time t=0,ant 1 starts approaching ant 2 with a speed v ant 2 tarts approaching ant 3 with speed v and ant 3 starts approaching ant 1 with a speed v. find the time when they meet. The angular velocity of ant 2 with respect to ant 1 at t=0 the angular acceleration of ant 2 with respect to ant 1 at t=0 the area of the equilateral triangle formed by the three ants at any time t=a/4v

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2 years ago

Himanshu Rathour
119 Points
```							Since it is an equilateral triangle hence angle between each side will be 60For ant 1 and 2Relative distance between them=aTheir relative velocity=v+vcos60=3v/2Hence time taken to cover relative distance a with velocity 3v/2T=2a/3vSimilary we can find out other time which will be sameAngular velocity of ant1 wrt ant2 =(velocity of ant1 perpendicular to line joining them+velocity of ant2 perpendicular to line joining them) /distance btw them=(0+v√3/2)/a=v√3/2a
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions