This question is of chapter center of mass.This question belongs to Conservation of linear momentum.
This question is of chapter center of mass.
This question belongs to Conservation of linear momentum.
Sparsh Jain , 6 Years ago
Grade 12th pass
IIT JEE Entrance Exam> This question is of chapter center of mas...
1 AnswersArun
Last Activity: 6 Years ago
Dear student
Assume that v1 and v2 be the velocity of bullet after collision.As the block raise to vertical distance of 0.1 m then kinetic energy converted into potential energy.From the law of conservation of energygh2^2 = m2v2½ m =√2gh2ð v = √2*9.8*0.12ð v= 1.4 m/sec2ð vu1 = initial velocity of bulletBy the law of conservation of momentum2v2+ m1v1 = m1u1ð m2v2 - m1u1= m1 v1ð m1)/ m2v2 - m1u1 = ( m1ð v =(0.01*500 – 2x1.4)/0.01 = (5-2.8)/0.01= 2.2/0.01= 220 m/sec
Regards
Arun (askIITians forum expert)
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