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This is a question taken from HC verma part 1. Can you please explain me how initially AO=2/3(root d^2- (d/2)^2) Please explain this solution to me

This is a question taken from HC verma part 1.
Can you please explain me how initially  AO=2/3(root d^2- (d/2)^2)
Please explain this solution to me

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Grade:11

1 Answers

Manas Shukla
102 Points
7 years ago
We know O is the centroid of triangle. if h is the height of the triangle then AO = 2h/3
Since h =(root d^2- (d/2)^2)
Thus AO = 2/3(root d^2- (d/2)^2)

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