IIT JEE Entrance Exam
this is a problem of rotational motion .please solve the problem
this is a problem of rotational motion .please solve the problem
1 Answer
Arun
Moment of Inertia of a rod = 12ML2
The kinetic energy is given as 21mvcm2+21Icmω2
or
211(102)+2112(1)(1)20.52122=
The kinetic energy is given as 21mvcm2+21Icmω2
or
211(102)+2112(1)(1)20.52122=
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