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this is a multicorrect question. please explain.thanks

naman gupta , 6 Years ago
Grade 12
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

particle is able to complete a circle ,
So at highest point mg = mv2/l
So v = \sqrt{gl}
intial velocity u to complete circle
(½)m(\sqrt{gl})2 – (½)mv2 = -mgl
So u = \sqrt{3gl}
After particle passes through initial position after completing circle.
So correct option is (B)
 

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