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There are three particles ABC which are situated at vertex of equilateral triangle ABCof side d at time T = 20 each of the particle moves with constant speed v always has its velocity along a b be always has be always has MC always has its velocity along CA at what time they will meet with each other
Dear Arvind velocity of A is v along AB the velocity of B is along BC . its component along BA is vcos60 = v/2. thus the separation AB decreases at the rate v+v/2=3v/2sice this rate is constt. the time taken in reducing the separation AB from d to 0 is t=d/(3v/2) =2d/3v
velocity of A is v along AB
the velocity of B is along BC . its component along BA is vcos60 = v/2. thus the separation AB decreases at the rate
v+v/2=3v/2
sice this rate is constt. the time taken in reducing the separation AB from d to 0 is
t=d/(3v/2) =2d/3v
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