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the volume of an air bubble is doubled as it rises from the bottom of the lake to its surface .The atmospheric pressure is 75cm of mercury.Ratio of density of mercuryto lake water is40/3.find depth of lake in metre.

the volume of an air bubble is doubled as it rises from the bottom of the lake to its surface .The atmospheric pressure is 75cm of mercury.Ratio of density of mercuryto lake water is40/3.find depth of lake in metre.

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear student
 

The pressure at the bottom of the lake is = The pressure due to hte air + The pressure due to the water column=P1

The pressure at the top is only the atmosphereic pressure=P2 Initial Vol=V1 and final Vol is =V2 

NOW YOU HAVEN'T MENTIONED ABOUT THE TEMP SO I AM CONSIDERING IT TO BE CONSTANT

So from gas eq we get P1V1=P2V2
V2=2V1 

Putting the values in the eq 1 we get,

H=10 meter


Regards

Arun (askIITians forum expert)

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