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The volume occupied by 1.008 gm of Hydrogen at STP is a. 22.4cc b. 11.2cc c. 22.4l d. 11.2l

The volume occupied by 1.008 gm of Hydrogen at STP is a. 22.4cc b. 11.2cc c. 22.4l d. 11.2l

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2 Answers

Arun
25750 Points
4 years ago
Now, as one mole of any gas occupies 22.4 litres of volume at STP, 1 mole of Hydrogen occupies 22.4 litres. Hence, 2 gm of Hydrogen occupies 22.4 litres of volume. So it is pretty obvious that 1 gm of Hydrogen gas occupies 11.2 litres at STP
Puja Nepal
13 Points
3 years ago
1 gm = 1000 mg
So, 1.008 mg = 1.008/1000
 
Weight in gm/ molar mass = volume/  22.4 l
(1.008/1000) / 2 = V/ 22.4 l
 
 
So, v = 11.2 l

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