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Grade: 11
        
The velocity v of a body moving along a straight line varies with time t as v=2t^2*e^-t,where v is in m/s and t is in second . The acceleration of body is zero at t=?
4 years ago

Answers : (2)

AUREA
61 Points
							
v=2t2et
then
a=2tet(t+2)
a=0 at t=0 or t=-2
since negative time has no physical significance, therefore t=0
4 years ago
nidhi mishra
25 Points
							
Given- 
v=2t2e-t
a=dv/dt =0= 2e-t (dt2/dt) + 2t2 (de-t/dt)
0= 4t e-t +2t2[ {de-t/d(-t)}×{d(-t)/dt }]
0= 4te-t - 2t2e-t
0= 2te-t (2-t)
Either 2te-t=0
t=0
Or 2-t =0
t=2
 
So t =0 or t=2
one year ago
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