The velocity v of a body moving along a straight line varies with time t as v=2t^2*e^-t,where v is in m/s and t is in second . The acceleration of body is zero at t=?

Question

AUREA · Answer

v=2t 2 e t then a=2te t (t+2) a=0 at t=0 or t=-2 since negative time has no physical significance, therefore t=0

nidhi mishra · Answer

Given- v=2t 2 e -t a=dv/dt =0= 2e -t (dt 2 /dt) + 2t 2 (de -t /dt) 0= 4t e -t +2t 2 [ {de -t /d(-t)}×{d(-t)/dt }] 0= 4te -t - 2t 2 e -t 0= 2te -t (2-t) Either 2te -t =0 t=0 Or 2-t =0 t=2 So t =0 or t=2

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The velocity v of a body moving along a straight line varies with time t as v=2t^2*e^-t,where v is in m/s and t is in second . The acceleration of body is zero at t=?

The velocity v of a body moving along a straight line varies with time t as v=2t^2*e^-t,where v is in m/s and t is in second . The acceleration of body is zero at t=?

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The velocity v of a body moving along a straight line varies with time t as v=2t^2*e^-t,where v is in m/s and t is in second . The acceleration of body is zero at t=?

The velocity v of a body moving along a straight line varies with time t as v=2t^2*e^-t,where v is in m/s and t is in second . The acceleration of body is zero at t=?

2 Answers

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