The velocity-time graph of a moving object is given in the figure. Find the maximum acceleration of the body and distance travelled by the body in the interval of time in which this acceleration exists.
Solution:
Acceleration is maximum when slope is maximum,
amax = (80-20)/(40-30) = 5m/s2
S = 20 m/s x 10 s + 1/2 x 6 m/s2 x 100s2 = 500m
My doubt is, in the above question, why can’t we find the distance travelled by the body by finding the area of v-t graph where the acceleration is maximum, i.e, distance=1/2 x 10 x 60=300.