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Grade 12Mechanics

the velocity of an object moving on a straight line as a function of time t is given as v= t2/3 – 5t2/2 + 6t the time at which acceleration of the particle will be negative is

Profile image of andrew smith
7 Years agoGrade 12
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2 Answers

Profile image of Ajay
7 Years ago
Differentiate the velocity with respect to time  and solve it by hit and trial... ÷*/¥¥*/%(%,*/(/*=,*=/¥*/,/*(*%/*(¥%(%
Profile image of Ajay
7 Years ago
I think at the place of (t^2)/3 it should be (t^3)/3  . if it is then differentiate velocity with respect to time  then it forms quadratic whose roots are 2 and 3 ...so accel^n is negative in open interval 2 to 3