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the velocity of an object moving on a straight line as a function of time t is given as v= t 2 /3 – 5t 2 /2 + 6t the time at which acceleration of the particle will be negative is

the velocity of an object moving on a straight line as a function of time t is given as v= t2/3 – 5t2/2 + 6t   the time at which acceleration of the particle will be negative is 

Grade:12

2 Answers

Ajay
11 Points
2 years ago
Differentiate the velocity with respect to time  and solve it by hit and trial... ÷*/¥¥*/%(%,*/(/*=,*=/¥*/,/*(*%/*(¥%(%
Ajay
11 Points
2 years ago
I think at the place of (t^2)/3 it should be (t^3)/3  . if it is then differentiate velocity with respect to time  then it forms quadratic whose roots are 2 and 3 ...so accel^n is negative in open interval 2 to 3

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