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the u tube having limbs contains mercury density pm to a level.ifthe left limbs is filled to the top with water pw then the rise of mercury level in the right limb will be
the pressure at the bottom would be same due to both the limbs.Hence pressure at bottom => pw*(h-x)*g + pm*g*(x) = p*mg*(h+y)=> pwgh – pwgx + pmgx = pmgh + pmgy=> y = (pw*(h-x)*g + pm*g*(x) – pmgh)/(pmg)is the answer.
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