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The two ends of a train moving with constant acceleration pass a certain point with velocity u and v. The velocity with which the middle point of the train passes the same point is?
We all know that,v2-u2=2as or v2=u2+2as -----> (1)a=v2-u2/2sNow for the mid-point of the trains1=s/2a1=v12-u2/2s1a1=v12-u2/2s/2a1=v12-u2/s or v12=u2 + as ----> (2)from (1) and (2) you will getas= v2-u2/2v12=u2 + asv12= v2+u2 /2HERE IS YOUR ANSWER HOPE THIS HELPS!THANKS
Two ends of a train moving with a constant acceleration pass a certain point with velcities uandv. Show that the velocity with which the middle point of the train passes the same point is `sqrt(9u"^(2) +v^(2)//2). or V=√(u2+v2)/2.
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