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The two blocks A and B having masses m = 5 kg and M = 25 kg as shown in the figure are free to move. The coefficient of friction between the blocks is 0.4, but the coefficient of friction between ground and M is zero. The minimum horizontal force F required to hold m against M is 30 K Newton, where K Is equal to

The two blocks A and B having masses m = 5 kg and M = 25 kg as shown in the figure are free to move. The coefficient of friction between the blocks is 0.4, but the coefficient of friction between ground and M is zero. The minimum horizontal force F required to hold m against M is 30 K Newton, where K Is equal to

Grade:12th pass

1 Answers

Arun
25750 Points
6 years ago
 
For the block with mass m not to slide down, 
μR = mg, where R = minimum force of action/reaction between the blocks 
=> R = 125N
=> minimum acceleration of the larger block 
a = 125/(25) m/s^2 
=> F (minimum) 
= (m+M)a 
= (30) * 5 
=150N
 
Hence 30 K  = 150
So
K= 5

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