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The toughest one IIT JEE ADVANCE problem
Find the displacement of the wedge when m comes out of the wedge. There is no friction anywhere.

pankaj rajput , 7 Years ago

Grade 12

1 Answers

Eshan

Since no external force acts on system in the horizontal direction, the center of mass remains at same place during whole process.
Therefore $m(-l)+m(lcos\theta)+Mx=0$
$\implies x=\dfrac{m}{M}l(1-cos\theta)$

Last Activity: 7 Years ago

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Mechanics> The toughest one IIT JEE ADVANCE problem ...

The toughest one IIT JEE ADVANCE problem Find the displacement of the wedge when m comes out of the wedge. There is no friction anywhere.

pankaj rajput , 7 Years ago

Eshan

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The toughest one IIT JEE ADVANCE problem
Find the displacement of the wedge when m comes out of the wedge. There is no friction anywhere.

A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.

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