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Grade 11Mechanics

The time taken by a particle performing SHM on a straight line to pass from a point A to B where its velocities are same is 2 seconds .After another 2 seconds it returns to B .What is the time period of oscillation in seconds??

Profile image of Thangellamudi Abhinay
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago
According to the question, a and b points are such that they are located at same distances from the equilibrium position. Here also it is said that velocity is same ,i.e; not only the magnitude but also the directions are same. So, total time period of oscillation = 2×( time taken to go from a to b + the next time taken to return at b) = 2×(2+2)= 8 sec(ans)