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Lokesh kumar Grade: 6
        
The time period of a satellite of earth is 5 hours If the separation between the earth and the earth and the satellite is increased to 4 times the previous value, the new time period will become
(a) 10 hours
(b) 80 hours
(c) 40 hours
(d) 20 hours
3 years ago

Answers : (3)

Deepak Patra
askIITians Faculty
474 Points
										(c)
According to Kepler’s law of planetary motion T2 ? R3 ? T2
= T1 (R2/R)3/2 = 5 x [4R/R]3/2
= 5 x 23 = 40 hour 
										
3 years ago
Chahat Gutpa
12 Points
										Time period = total distance/velocityT=2πr/√grT`=2π(4r)/√g(4r)T`=4(2πr)/2√grT`=2(2πr)/√grT`=2TT`=2×5T`=10 hours(option A)
										
2 months ago
Chahat Gutpa
12 Points
										Time period = total distance/velocity   T =2πr/√gr                                       T`=2π(4r)/√g(4r)                    T`=4(2πr)/2√gr.                              T`=2(2πr)/√gr                  T`=2T                                         T`=2×5T`=10 hours(option A)
										
2 months ago
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