Flag Mechanics> The threshold wave length of photosensiti...
question mark

The threshold wave length of photosensitive metal is 5000 A find the K.E of the photo electrons emmited by it pt radiation of wave length 4000A incident on it explain in ev

Binita , 7 Years ago
Grade 12th pass
anser 1 Answers
vipul singh

Last Activity: 7 Years ago

Threshold wavelength( λ¹) = 5000A ∴ threshold energy(ф)= hc/λ¹= 12400/5000 ev = 2.48 ev Wavelength of radiation(λ) = 4000A ∴ energy of radiation(E)= hc/λ = 12400/4000 ev = 3.1 EV Since E = ф + K.E.(max.) 3.1 = 2.48 + K.E.(max) K.E.(max) = 0.62 ev

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...