Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
The tension in a string holding a solid block below the surface of a liquid (of density greater than the solid) is T0when the containing vessel (Fig. 15-18) is at rest. Show that the tension T, when the vessel has an upward vertical acceleration a, is given by T 0 (1 + a/g).
When the vessel is moving with an upward vertical acceleration a, there is net forces acting on the block. So, there is change in the buoyant force and the tension in the string.The figure which shows the forces acting on the block when the vessel is accelerating upward isThis represents the tension in the string when the vessel is accelerating upward.
Dear Student,Please find below the solution to your problem.Let m be the mass of block.Initially fore the equilibrium of block.F=T0+mg ------------------(1)Here, F is the upthrust on the bl;ockwhen the lift is accelerated upwards, get becomes g+ a instead of g.Hence,F′=F(g+a)/g--------------------(2)From newton's second law,F′−T−mg=ma-----------------(3)Solving eqn (1),(2) and (3), we getT=T0(1+ga)Thanks and Regards
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -