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Grade upto college level Mechanics

The tension in a string holding a solid block below the surface of a liquid (of density greater than the solid) is T0when the containing vessel (Fig. 15-18) is at rest. Show that the tension T, when the vessel has an upward vertical acceleration a, is given by T₀(1 + a/g).

Amit Saxena

11 Years agoGrade upto college level

2 Answers

Navjyot Kalra

11 Years ago

When the vessel is moving with an upward vertical acceleration a, there is net forces acting on the block. So, there is change in the buoyant force and the tension in the string.
The figure which shows the forces acting on the block when the vessel is accelerating upward is

This represents the tension in the string when the vessel is accelerating upward.

Rishi Sharma

5 Years ago

Dear Student,
Please find below the solution to your problem.

Let m be the mass of block.
Initially fore the equilibrium of block.
F=T0+mg ------------------(1)
Here, F is the upthrust on the bl;ock
when the lift is accelerated upwards, get becomes g+ a instead of g.
Hence,
F′=F(g+a)/g--------------------(2)
From newton's second law,
F′−T−mg=ma-----------------(3)
Solving eqn (1),(2) and (3), we get
T=T0(1+ga)

Thanks and Regards

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