the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=
J.Mouryan , 7 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 7 Years ago
Dear Student,
Speed at max ht=ucos=√(3/2) u =>=30⁰
Range=u2sin2/g =u2√3/20
height= u2sin2/2g =u2/80 ATQ, u2√3/20=p x u2/80 =>p=4√3
Cheers!!
Regards,
Vikas (B. Tech. 4th year Thapar University)
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