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the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=

J.Mouryan , 7 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
Speed at max ht=ucos=√(3/2) u
=>=30⁰
Range=u2sin2/g
=u2√3/20
height= u2sin2/2g
=u2/80
ATQ,
u2√3/20=p x u2/80
=>p=4√3
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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