the speed of a paricle moving in a cirle of radius 61/2 m is increasing 3 m/s2 . find net acceleration at t=2 sec ( Given, v=0, at t=0 )

tangential acceleration = 3 m/s2velocity after 2 sec = 3*2 = 6 m/sso radial acceleration = v2/r =6 m/s2ao total acceleration = Hopeit clears If yo like answer then please approve it.

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Grade 12th passMechanics

the speed of a paricle moving in a cirle of radius 6^1/2m is increasing 3 m/s² . find net acceleration at t=2 sec ( Given, v=0, at t=0 )

Soumya Swaraj Kuila

7 Years agoGrade 12th pass

1 Answer

Khimraj

7 Years ago

tangential acceleration = 3 m/s²

velocity after 2 sec = 3*2 = 6 m/s

so radial acceleration = v²/r =6 $\sqrt{6}$ m/s²

ao total acceleration = $\sqrt{3^{2} + (6\sqrt{6})^{2}} = 15 m/s^2$

Hopeit clears If yo like answer then please approve it.

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the speed of a paricle moving in a cirle of radius 61/2 m is increasing 3 m/s2 . find net acceleration at t=2 sec ( Given, v=0, at t=0 )

Soumya Swaraj Kuila

1 Answer

Khimraj

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the speed of a paricle moving in a cirle of radius 6^1/2m is increasing 3 m/s² . find net acceleration at t=2 sec ( Given, v=0, at t=0 )

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