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`        The speed of a bus increases from 50 kilometre Hawa 270 kilometre Hawa is 5 second find the mean acceleration of the bus`
2 years ago

```							Funal velocity v=70*1000/3600 =19.4 m/sInitial velocity u =50*1000/3600=13.88 m/st= 5 secondacceleration = a = (19.4 -13.88)/5= 5.52/5= 1.104 m/s^2
```
2 years ago
```							DEAR,For calculating acceleration use 1st equation of motion , v=u+athere,v = final velocity =270km/hru = initial velocity=50km/hrt = 5second=5/3600hrNow, putting the value in equation , 270=50+a.5/3600or, a=220 x 3600/5=158400km/hr .REGARDSAdarsh

DEAR,
For calculating acceleration use 1st equation of motion , v=u+at
here,
v = final velocity =270km/hr
u = initial velocity=50km/hr
t = 5second=5/3600hr
Now, putting the value in equation , 270=50+a.5/3600
or, a=220 x 3600/5=158400km/hr .
REGARDS

```
2 years ago
```							mean =220\5
=44
hope it helps please approve if it does
```
2 years ago
```							Funal velocity v=70*1000/3600 =19.4 m/sInitial velocity u =50*1000/3600=13.88 m/st= 5 secondacceleration = a = (19.4 -13.88)/5= 5.52/5= 1.104 m/s^2/////////////////////kjkhiu    jgj
```
2 years ago
```							DEAR,For calculating acceleration use 1st equation of motion , v=u+athere,v = final velocity =270km/hru = initial velocity=50km/hrt = 5second=5/3600hrNow, putting the value in equation , 270=50+a.5/3600or, a=220 x 3600/5=158400km/hr .
```
2 years ago
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