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Grade: 6
        
The range of a projectile fired at angle 15degrees is 50m. If it is fired with same speed with an angle of 45degrees.
one year ago

Answers : (1)

Ghufran Amanullah
26 Points
							First we find the velocity by given dataAngle=15° ,Range=50 m, taking g=9.81 m/sR=Vo^2*sin2(angle)/g50=Vo^2*sin2(15)/9.8150=Vo^2*0.5/9.81        (since sin(30)= 0.5)490.5=Vo^2*0.5            (9.81*50=490.5)980=Vo^2Hence Vo=31.31Now again subsituting Vo=31.31, angle=45° and g=9.81R=(31.31)^2*sin2(45)/9.81R=980*1/9.81      (since sin(90)=1)R=100 mThe final result is R=100 m
						
one year ago
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