Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        The range of a projectile fired at angle 15degrees is 50m. If it is fired with same speed with an angle of 45degrees.`
2 years ago

Ghufran Amanullah
26 Points
```							First we find the velocity by given dataAngle=15° ,Range=50 m, taking g=9.81 m/sR=Vo^2*sin2(angle)/g50=Vo^2*sin2(15)/9.8150=Vo^2*0.5/9.81        (since sin(30)= 0.5)490.5=Vo^2*0.5            (9.81*50=490.5)980=Vo^2Hence Vo=31.31Now again subsituting Vo=31.31, angle=45° and g=9.81R=(31.31)^2*sin2(45)/9.81R=980*1/9.81      (since sin(90)=1)R=100 mThe final result is R=100 m
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions