Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        the radius of gyration of a solid sphere of radius r about a certain axis is r. the distance of this axis from the centre of the sphere is √0.6r explain???`
3 years ago

Unknown aspirant
13 Points
```							Using parallel axis theorem ,I =Icm(about the centre of mass) + M(mass of the sphere)h2.    where h is the required distance of the axis from centre of sphereMK2 = 2/5 MR2. + Mh2 K2= 2R2/5 + h2R2 = 2R2/5. +  h2.       (given that.  K=R. )3R2/5 = h2Which gives h=√3/5R2h=√0.6. R.   (Answer)R MK
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions