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the radius of gyration of a solid sphere of radius r about a certain axis is r. the distance of this axis from the centre of the sphere is √0.6r explain???
2 years ago

Unknown aspirant
13 Points

Using parallel axis theorem ,
I =Icm(about the centre of mass) + M(mass of the sphere)h2.    where h is the required distance of the axis from centre of sphere
MK2 = 2/5 MR2. + Mh
K2= 2R2/5 + h2
R= 2R2/5. +  h2.       (given that.  K=R. )
3R2/5 = h2
Which gives h=√3/5R2
R

MK
11 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions