Last Activity: 5 Years ago
velocity of A is v along AB
the velocity of B is along BC . its component along BA is vcos60 = v/2. thus the separation AB decreases at the rate
v+v/2=3v/2
sice this rate is constt. the time taken in reducing the separation AB from l to 0 is
t=l/(3v/2) =2l/3v
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Last Activity: 2 Year ago(s)