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The potential energy of certain spring when stretched through a distance s is 10 joule.The amount of work that must be done on this spring to stretch it through additional distance s will be

The potential energy of certain spring when stretched through a distance s is 10 joule.The amount of work that must be done on this spring to stretch it through additional distance s will be

Grade:9

2 Answers

Arun
25750 Points
5 years ago
Dear Navya
 
P. E. to stretch through x is = 
 
½ k* x^2 = 10
 
to tretch through additional distance x
 
½ k (4s^2 – s^2 ) = 3/2 * k* s^2 = 3 * 10 = 30 Joules
Komal
15 Points
4 years ago
PE = 1/2kx^2
U1= 1/2ks^2 = 10 j ............eq(1) 
Addition length of spring is =S
Total lenght =2s
U2=1/2k(2s) ^2
W. Done = u2 -u1 
                = 1/2k(2s)^2 - 1/2ks^2
                = (1/2ks^2)4 - 1/2ks^2
  { Here replace the value of 1/2ks^2 =10}
                = 10×4 - 10
                 =40 - 10
                 = 30j
 
 
 
 
 
 
 
 
 
 
 
                = 1/2 ×k 4s^2  - 1/2ks^2
                  =4(1/2ks^2) - 

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