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The positioncoordinates of an object are given by x=2t^2,y=t^2-4 t,z=3t-5 . The average velocity of particle during the interval of 0-1sec

The positioncoordinates of an object are given by x=2t^2,y=t^2-4 t,z=3t-5 . The average velocity of particle during the interval of 0-1sec

Grade:11

1 Answers

Vikas TU
14149 Points
4 years ago
Hiii Alisa 
Write down the displacement in vector form.
S= xi^ + yj^ + zk^ 
we know that derivative of s = velocity.
Take erivative and put the value of t as 1 this would be v1.
again take derivative and put the value of t as 0. This would be v2
average velocity = Total distance travelled / total time taken 
So find s magnitude  by putting t=0 and at t=1 .
Add them and divide by 1 . 
This would be average velocity, and ans is 8.38 m/sec.
 

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