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The positioncoordinates of an object are given by x=2t^2,y=t^2-4 t,z=3t-5 . The average velocity of particle during the interval of 0-1sec
Hiii Alisa Write down the displacement in vector form.S= xi^ + yj^ + zk^ we know that derivative of s = velocity.Take erivative and put the value of t as 1 this would be v1.again take derivative and put the value of t as 0. This would be v2average velocity = Total distance travelled / total time taken So find s magnitude by putting t=0 and at t=1 .Add them and divide by 1 . This would be average velocity, and ans is 8.38 m/sec.
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