Mechanics> The positioncoordinates of an object are ...

The positioncoordinates of an object are given by x=2t^2,y=t^2-4 t,z=3t-5 . The average velocity of particle during the interval of 0-1sec

Alisha , 6 Years ago

Grade 11

1 Answers

Vikas TU

Hiii Alisa

Write down the displacement in vector form.

S= xi^ + yj^ + zk^

we know that derivative of s = velocity.

Take erivative and put the value of t as 1 this would be v1.

again take derivative and put the value of t as 0. This would be v2

average velocity = Total distance travelled / total time taken

So find s magnitude by putting t=0 and at t=1 .

Add them and divide by 1 .

This would be average velocity, and ans is 8.38 m/sec.

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Mechanics> The positioncoordinates of an object are ...

The positioncoordinates of an object are given by x=2t^2,y=t^2-4 t,z=3t-5 . The average velocity of particle during the interval of 0-1sec

Alisha , 6 Years ago

Vikas TU

LIVE ONLINE CLASSES

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