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The position vector of a particle is given by the expression r(vector) = 4t^2i+3t^2j+9k. The displacement traversed by the particle in first 10 s is

Ishan karki , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

r (i)= Initial position vector
r (f) = Final position vector
Since r is the finction of time.
r(i)=r(0)=9 k^   
r(f)=r(10)=4*10² i^ + 3*(10)² j^ +9 k^
Now ,
Displacement vector= r(f)-r(i)
D= |400 i^ + 300j^ +(9-9)k^ |
=500
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