The position of a particle along the x axis at time t is given by x= 1+t-t^2. The distance travelled by it in first 2s is.

Question

Vaibhav Singh · Answer

Integrate x with respect to t from 0 to 2 s.Distance will be 4/3 unit.Since it doesn`t allow here to post solution in the form of pic. So you may proceed like I stated.

Pranjul · Answer

You are wrong this method is applied when direction is not charged but in this question differentiate it and put 0 in velocity you will get. 5 seconds now distance =/(x(0) - x(. 5)/ +/(x(0) - x(2)/ you will get 2.5m ans

Annapurna Rawat · Answer

I did as you say. But I got the answer 3.5 instead of 2.5. By putting value of v=0 I got t=0.5s and got 1.25 b which I multiplied with 2 and got 2.5. But for t=2 displacement was -1. So I added 1 and my answer was 3.5. Did I make a mistake in my procedure?

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The position of a particle along the x axis at time t is given by x= 1+t-t^2. The distance travelled by it in first 2s is.

The position of a particle along the x axis at time t is given by x= 1+t-t^2. The distance travelled by it in first 2s is.

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The position of a particle along the x axis at time t is given by x= 1+t-t^2. The distance travelled by it in first 2s is.

The position of a particle along the x axis at time t is given by x= 1+t-t^2. The distance travelled by it in first 2s is.

3 Answers

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