Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        The period of a pendulum on two planets are in the ratio 3:4the acceleration due to gravity on them are in ratio  `
2 months ago

Arun
23523 Points
```							 Dear student  As we know T = 2 pi sqrt (L/g) hence T1 /T2 = sqrt (g2/g1) ¾ = sqrt (g2/g1) hence g1 / g2 = 16/9
```
2 months ago
Vikas TU
10078 Points
```							Dear student Timeperiod of pendulum = T = 2pie√(L/g)T^2 is directly proportional to 1/g g is directly proportional to 1/T^2 g1/g2 = (T2/T1)^2 g1/g2 = 16/9 Hope this helps
```
2 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions