Grade 11Mechanics
The period of a pendulum on two planets are in the ratio 3:4the acceleration due to gravity on them are in ratio
The period of a pendulum on two planets are in the ratio 3:4the acceleration due to gravity on them are in ratio
2 Answers
Arun
Dear student
As we know T = 2 pi sqrt (L/g)
hence
T1 /T2 = sqrt (g2/g1)
¾ = sqrt (g2/g1)
hence g1 / g2 = 16/9
Vikas TU
Dear student
Timeperiod of pendulum = T = 2pie√(L/g)
T^2 is directly proportional to 1/g
g is directly proportional to 1/T^2
g1/g2 = (T2/T1)^2
g1/g2 = 16/9
Hope this helps
Timeperiod of pendulum = T = 2pie√(L/g)
T^2 is directly proportional to 1/g
g is directly proportional to 1/T^2
g1/g2 = (T2/T1)^2
g1/g2 = 16/9
Hope this helps
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