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`        The period of a particle executing SHM is 8 s. At t= 0 it is at the mean position. The ratio of the distances covered by the particle in the 1st second to the 2nd second is`
one year ago

Arun
22985 Points
```							let the equation of motion is X =Asin(2px/8) in first second X1 =Asin(p/4) in 2 sec X2 =Asin(p/2) so 2nd sec distance covered = X2 -X1 x1 /(X2 -X1) = Asin(p/4)/[Asin(p/2) -Asin(p/4)] =1/(v2 -1
```
one year ago
AKSHANSH PAREEK
68 Points
```							Y¹= A sin w = A sin 2π\8 = A /√2 Distance when t=2 sec isY²= A sin w= A sin π\2= A Distance covered in 2sec is A-A/√2 Y¹/Y²= (A/√2) / (A-A/√2) = 1/√2-1please approve
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions