The PE of a particle varies with x according to the relation U(x)=x^2-4x. The point x=2 is a point of

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Arun · Answer

At x = 2 P.E = 2² - 4*2 = 4 - 8 = -4 Hence this is a point where p.e. is negative. Regards Arun (askIITians forum expert)

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The PE of a particle varies with x according to the relation U(x)=x^2-4x. The point x=2 is a point of

The PE of a particle varies with x according to the relation U(x)=x^2-4x. The point x=2 is a point of

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The PE of a particle varies with x according to the relation U(x)=x^2-4x. The point x=2 is a point of

The PE of a particle varies with x according to the relation U(x)=x^2-4x. The point x=2 is a point of

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