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Grade: 11
        The PE of a particle varies with x according to the relation U(x)=x^2-4x. The point x=2 is a point of
7 months ago

Answers : (1)

Arun
12364 Points
							
At x = 2
P.E = 2² - 4*2 = 4 - 8
 = -4
 
Hence this is a point where p.e. is negative.
 
Regards
Arun (askIITians forum expert)
7 months ago
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