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`        the only force acting on a 2.0 kg body as it moves along the x axis has an x component f = -6x where x is in meters. the velocity of body at x = 3m is 8m/s. 	what is the velocity at x=4m	at what position value of x will have v = 5m/s`
one year ago

Pavan Kumar
32 Points
```							hey, thank you for asking the question man, the first thing you need to know    f=m*v*dv/dx                        force=mass*velocity*derivative of velocity w.r.t displacement                        proof:   f=m*a     [a=accleration]                                     a=dv/dt   *  [ dx/dx]                                     a=dv/dx  *  dx/dt                                       = dv/dx * v                                    f=m*dv/dx * vso   given f=-6x                             f= 2 * v* dv/dx = -6x                                 v dv = -3xdx                                  v2/2 = -3x2/2 + constant                              given at x=3 , v= 8 substituting in the above equation we get  c= 91/2                                     so just substitute the given readings that they have asked have a good day.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions