Last Activity: 4 Years ago
dv)/dt = 1-2vdv (1/(1-2v) = dtNow,integrating both sides we get,(-1/2)×ln(1- 2v) = t .....Zero initial conditions ,hence c=0ln(1- 2v) = -2t1 -2v = e^-2tv = (1 - e^-2t)/2This is the required velocity time relation
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Last Activity: 2 Year ago(s)