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The momentum of a body in two perpendicular directions at any time t are given by px =2t^2 + 6 and py =3t^2 /2 +3 . The force acting on the body at t =2 sec is The momentum of a body in two perpendicular directions at any time t are given by px =2t^2 + 6 and py =3t^2 /2 +3 . The force acting on the body at t =2 sec is
Find force in x and y directions at 2 secs.Then calculate the net resultant force by taking square of the sume of each force components squared value.
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