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`        The moment of interia of a triangular lamina of mass M and height H about its base`
one year ago

harshin nechooli
121 Points
```							Main asking for moment of inertia you should first specify the axis of rotation I think it is on the base.        the     MHsq ÷6
```
one year ago
Khimraj
3008 Points
```							Mass per unit area= M 1/2 ahbase= aMoment of inerta= I = 1/2 x M/1/2ah x 1/2ax x xdxx is the small strip along h from baseSo, moment of inertia at base = 1/2 x M/h limit x².dx = M/2h (x³/ 3) = M/2h . h³/3 = Mh²/6
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions