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The moment of interia of a triangular lamina of mass M and height H about its base

Ananya , 6 Years ago
Grade 11
anser 2 Answers
harshin nechooli

Last Activity: 6 Years ago

Main asking for moment of inertia you should first specify the axis of rotation I think it is on the base.        the     MHsq ÷6

Khimraj

Last Activity: 6 Years ago

Mass per unit area= M 1/2 ah
base= a
Moment of inerta= I = 1/2 x M/1/2ah x 1/2ax x xdx
x is the small strip along h from base
So, moment of inertia at base = 1/2 x M/h limit x².dx 
= M/2h (x³/ 3) 
= M/2h . h³/3 
= Mh²/6

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