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Grade 11Mechanics

The moment of inertia of sphere is 40kg m^2 about the diameter. Determine the moment of inertia about any tangent

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8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To determine the moment of inertia of a sphere about a tangent, we can use the parallel axis theorem. This theorem states that if you know the moment of inertia of an object about an axis through its center of mass, you can find the moment of inertia about any parallel axis by adding the product of the object's mass and the square of the distance between the two axes.

Understanding the Given Information

In your case, the moment of inertia of the sphere about its diameter (which passes through its center) is given as 40 kg·m². We need to find the moment of inertia about a tangent to the sphere. First, let's identify the necessary parameters:

  • I_center: Moment of inertia about the center (40 kg·m²)
  • m: Mass of the sphere (we'll need to calculate this)
  • r: Radius of the sphere (we'll also need to calculate this)

Calculating Mass and Radius

The moment of inertia of a solid sphere about its center is given by the formula:

I_center = (2/5) * m * r²

From this, we can express the mass in terms of the radius:

m = (5/2) * (I_center / r²)

Applying the Parallel Axis Theorem

Now, we need to find the moment of inertia about a tangent. The distance from the center of the sphere to the tangent line is equal to the radius of the sphere (r). According to the parallel axis theorem, the moment of inertia about the tangent axis (I_tangent) can be calculated as follows:

I_tangent = I_center + m * r²

Substituting Values

Now, substituting the values we have:

I_tangent = 40 kg·m² + m * r²

We can replace m using the earlier expression:

I_tangent = 40 kg·m² + (5/2) * (I_center / r²) * r²

This simplifies to:

I_tangent = 40 kg·m² + (5/2) * I_center

Substituting I_center = 40 kg·m²:

I_tangent = 40 kg·m² + (5/2) * 40 kg·m²

I_tangent = 40 kg·m² + 100 kg·m² = 140 kg·m²

Final Result

Thus, the moment of inertia of the sphere about a tangent is 140 kg·m². This approach illustrates how the parallel axis theorem allows us to shift our axis of rotation while accounting for the distribution of mass relative to the new axis.