MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
The moment of  inertia of a uniform semicircular wire of mass M and radius R about a line perpendicular to the plane of the wire through the centre is
2 months ago

Answers : (2)

Arun
22595 Points
							
The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire through the center is
''Mr²''. 

Explanation ⇒ According to the question, the mass of the wire is at a distance r away from the axis. 
We know that the moment of the Inertia in such case will be given by the formula, 
 Moment of Inertia = Mv²
where, m is the mass and r is the Perpendicular distance. 

 
 
2 months ago
Vikas TU
8825 Points
							
Dear student 
Using Parallel Axis Theorem of MI
I1=I+mx^2
where I1= Moment of inertia about centre=mr^2
and I= Moment of inertia about centre of mass which is required
x=2r/π(distance between centre of mass of wire and its geometrical centre) THUS
I=I1−m(2r/π)^2
I=mr^2[1−4/π^2]
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details