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`        The moment of inertia of a uniform rod of mass .50 kg and length 1 m is .10kgm2 about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.plz explain  the ans.`
one year ago

Arun
23513 Points
```							Given in the question,Length of the Rod - 1 mMass of the Rod - 0.5 gMoment of Inertia at perpendicular bisectorI = ml^2 / 12=0.50 × 1² /12=1/ 24 kg.mAt the distance r the moment of inertia , rod middle point l' = 0.10 kg-m²I’ = I + m r^20.10 = 1/ 24 +0.50 r²1+0.50× 24 r² =0.10× 2412 r² =2.4 -1r² =1.4/12 r²=0.467/4r= 0.68/2r= 0.34 m.Hence the distance from the middle point is equal to 0.34 m.
```
one year ago
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