Rituraj Tiwari
Last Activity: 4 Years ago
Given parameters
Moment of inertia of a square lamina about the perpendicular axis at the center of the square (I0) = 20 kgm-2
Let us consider
L = Length of square
M = Mass of the square laminaI0=ML2620 = ML2/6
ML2= 120 kgm2
According to the parallel axis theorem
Ix= Iy= I0/2= 10kgm-2
I1= Ix+ M(L/2)2
⇒ I1= Ix+ ML2/4
⇒ I1= 10 + 120/4
⇒ I1= 40 kgm-2