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Grade 11Mechanics

the moment of inertia of a solid flywheel of radius 0.1m about its axis is 0.1kgm2. a tangential force of 2 kg wt is applied through the circumference of flywheel with the help of string and mass M. the acceleration of the mass is

Profile image of Vansh Goyal
9 Years agoGrade 11
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1 Answer

Profile image of Adikesh Kumar
9 Years ago
ANS: 2m/s2
equate the torque 
I alpha = force * r  (r = radius of wheel)
0.1*a/r = 2*10* r    ( a = accelaration)
therefore a=2m/s ( r = 0.1m)