×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
the moment of inertia of a solid flywheel of radius 0.1m about its axis is 0.1kgm2. a tangential force of 2 kg wt is applied through the circumference of flywheel with the help of string and mass M. the acceleration of the mass is

```
4 years ago

26 Points
```							ANS: 2m/s2equate the torque I alpha = force * r  (r = radius of wheel)0.1*a/r = 2*10* r    ( a = accelaration)therefore a=2m/s2  ( r = 0.1m)
```
4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions